A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity components are 9.8m/s and 19.6 m/s respectively. Its horizontal range is:

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Explanation:

Let horizontal component of velocity be Vx = vcosθ and vertical be Vy = vsinθ

Therefore, velocity is:

Vx = vcosθ and vertical be Vy = vsinθ

Final Answer:

Hence, option (D) is correct. (39.2 m)

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