A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is 0.2 × T , then the e.m.f developed between the two ends of the conductor is

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Explanation:

The emf induced between the two conductors 

e=1/2 Bωr^2 [where B is the magnetic field ,ω is the angular velocity r is the radius

⇒e=1/2×0.2×〖10〗^(-4)×5×〖(1)〗^2

⇒e=50μV

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