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If the top andthe bottom rungs are 2.5 m apart, what isthe length of the wood required for therungs?
[Hint : Number of rungs=250/25]
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Number of rungs can be calculated as follows:
2.5 x 100 cm ÷ 25 + 1
= 2.5 x 4 + 1
= 10 + 1 = 11
We have; a = 25, a11 = 45 and n = 11
d can be calculated as follows:
a11 = a + 10d
45 = 25 + 10d
10d = 45 – 25 = 20
d = 2
Total length of wood will be equal to the sum of 11 terms:
= 8[ 25 + (10)]
= 11 *35
= 385 cm
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