If the top andthe bottom rungs are 2.5 m apart, what isthe length of the wood required for therungs?

           [Hint : Number of rungs=250/25]

Arithmetic

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 Number of rungs can be calculated as follows:

2.5 x 100 cm ÷ 25 + 1

= 2.5 x 4 + 1

= 10 + 1 = 11

We have; a = 25, a11 = 45 and n = 11

d can be calculated as follows:

a11 = a + 10d

45 = 25 + 10d

10d = 45 – 25 = 20

d = 2

Total length of wood will be equal to the sum of 11 terms:

Arithmetic

                 = 8[ 25 + (10)]

                 = 11 *35

                 = 385 cm

 

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