A given metal crystallizes out with a cubic structure having edge length of 361 pm.

Explanation:

There are four metal atoms in one unit cell, the unit cell is fcc type.

For the fcc unit cell,

4r = √2 a

r = √2/4a

r = 0.3535 a,

where, a is the edge length of the unit cell and r is radius

Then r=0.3535×361 pm =127.6 pm

So, the radius of one atom is 127.6 pm.

Final answer:

(D) 127.6 pm