A certain metal when irradiated by light ( r = 3.2 × 1016Hz ) emits photoelectrons with twice kinetic energy

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A certain metal when irradiated by light ( r = 3.2 × 1016Hz ) emits photoelectrons with twice kinetic energy as did photo electrons when the same metal is irradiated by light ( r = 2.0 × 1016Hz ) . The V0 of metal is:

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The formula for kinetic energy is

KE1= h (V1 - V0)

KE2= h (V2-V0)= KE1/2 (Given)

KE2KE1= (V2-V0)V1-V0)=1 2

4.0 × 1016- 2V0= 3.2 × 1016- V0

V0= 8 × 1015Hz

Hence the correct answer is option (B) V0= 8 × 1015Hz

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