A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of

Explanation:

Mass of body, m = 2kg

Force applied on body, F = 7N

Coefficient of kinetic friction, μ = 0.1

Initial velocity, υ = 0

Time, t = 10s

Final Answer:

(a) Hence, the work done by the applied force in 10 s is 882J.

(b) Hence, the work done by friction in 10 s is 635J.

(c) Hence, the work done by the net force on the body in 10 s is 5.04 N.

(d) Hence, the change in kinetic energy of the body in 10 s is 635J.