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We have a 12pF capacitor connected to a 50V battery.

So, the total energy of Capacitor is:

E = 1/2CV2

= 1/2  x 12 x 10-2  x 502

&= 1.5 x 10-8 

The electrostatic energy is stored in the capacitor is =  1.5 x 10-8 J

solved 5
wordpress 4 mins ago 5 Answer 70 views +22

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