Report Question Solution: Given: In ΔPQR, ∠PQR = ∠PRQ PQ = PR (i) Given, Using (i), In triangle PQS and TQR, we get [Using (i)] ∠Q = ∠Q Therefore, Triangle PQS TQR (SAS similarity rule) solved 5 wordpress 4 mins ago 5 Answer 70 views +22
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